The length of each side of a rhombus is 8cm. and its one angle is
60⁰.Find the length of the diagonals of the rhombus.
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In triangle AOB,
<OAB=30°(Diagonals of rhombus bisect the angles)
<A+<B=180°(Co int. <s)
60+<B=180°
<B=120°
<OBA=120/2 i.e.60°(Same statement)
A.T.Q-
sin 30°=OB/8
°•° sin 30°=1/2
•°•1/2=OB/8
By cross multiplication
OB=4 cm
•°•BD=4+4 i.e.8 cm
Now,
sin 60°=OA/8
rt3/2=OA/8
By cross multiplication
OA=4rt3
•°•AC=4rt3+4rt3 i.e.8rt3
LENGTH OF DIAGONALS IS-
8 CM , 8RT3 CM
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