the length of each side of rhombus is 10cm and one of its diagonal is 16 cm. what is the length of other diagonal plzzz give me answer fast
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AB = 10 cm is the hypotenuse
AO = 8 cm (half of AC as diagonals bisect)
hence in the triangle ABO , using Pythagorean theorem ,
AO2+BO2=AB2
BO2+82=102
BO2+64=100
BO2=100−64==>36
√(BO2)=√36
BO = 6 cm
therefore diagonal BD=2∗BO
BD = 12 cm
hence area of rhombus = 1/2 * AC * BD
[1/2∗(16∗12)]cm2
96 cm^2
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