Question

the length of equal sides of an isosceles triangle is16.7find the length of third side if it's perimeter is 50 ​

Answer 1

Answer: b= 16.6

Step-by-step explanation:

first side = 16.7

second side = 16.7 (as two sides are equal)

third side=?

perimeter = 50

P=2a+b

50=2(16.7)+b

b= 16.6

hope helps u !!!!!

Answer 2

Answer:

$\huge\fbox\red{60sq cm }$

Step-by-step explanation:

Let the third side of the isosceles triangle = a

perimeter of the triangle = sum of all sides = 13+13+a= 50 ==>a=24

Let the sides of the length, base of the triangle.

since the height of the triangle, divides it into two right angled triangles,

${13}^{2} = {h}^{2} + {12}^{2}$

${h}^{2} = 169 - 144 = 24$

$h = \sqrt{25} = 5 \: cm$

$now \: area \: of \: the \: triangle \: = \frac{1}{2} \times base \times height \: = \frac{1}{2} \times 25 \times 5 = 60 \: sq \: cm$

$\huge\fbox\red{Thank you}$