Question

the length of equator of the globe is 22cm.find its surface area​

Answer 1

Given:-

• Length of equator of the globe is 22 cm.

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To find:-

• Surface area of the globe.

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Solution:-

• Length of the equator of the globe or circumference of a globe = 44cm

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Let,

• the radius be x.

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☆Circumference of the globe = 2πr

→ 44 = 2 × 22/7 × x

→ x = 44 × 7/44

→ x = 7

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Then,

☆Surface area of the globe = 4πr²

→ 4 × 22/7 × (7)²

→ 616 cm²

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Hence,

• the surface area of the globe is 616 cm².

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⠀⠀⠀⠀⠀⠀Some Formulae

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→ Area of square = (side)²

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→ Area of rectangle = length × breadth

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→ Area of triangle = ½ × base × height

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→ Area of parallelogram = base × height

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→ Area of Circle = πr²

Answer 2

☯GIVEN:-

• Lenght of equator of globe is 22cm.

☯TO FIND:-

• Find surface area of globe.

☯ UNDERSTANDING:-

Here, We will furer find circumference of the globe.

Circumference of the globe is 44cm.

• Now let us find the circumference of the globe.

✞Circumference of globe = 2πr

$\implies \sf {44 = 2 \times \pi \times r}$

$\implies \sf {44 = 2 \times \frac{22}{7} \times r}$

$\implies \sf {44 = \frac{44}{7} \times r}$

$\implies \sf {r= 44 \times \frac{7}{44}}$

$\implies \sf {r= 7}$

Now,

✞Surface area of globe = 4πr²

$\implies \sf 4 \times \pi \times {r}^{2}$

$\implies \sf 4 \times \frac{22}{7} \times {7}^{2}$

$\implies \sf 4 \times \frac{22}{7} \times 14$

$\implies \sf 616 {cm}^{2}$

$\large { \boxed{ \underline{ \bf{ \pink{Hence, \: the \: surface \: area \: of \: globe \: is \: 616cm². }}}}}$

$\rule{300}{1.5}$