Math, asked by jiyatomar40, 3 months ago

The length of hall exceeds its breadth by 12m.If the perimeter of hall is 76 m, find the cost of carpeting it at Rs4 per sq.m.

Answers

Answered by BrutalShadow
5

Answer:

\huge\colorbox{Brown}{Answer ☝}

Attachments:
Answered by SuitableBoy
88

{\huge{\boxed{\underline{\overline{\rm{Question:-}}}}}}

Q) The length of a hall exceeds it's breadth by 12m . If the perimeter of the hall is 76m , find the cost of carpeting it at Rs 4 per sq. m.

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{\huge{\underbrace{\rm{Answer\checkmark}}}}

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\frak{Given}\begin{cases}\rm{The\:\bf{length}\:exceeds\:the\:\bf{breadth}\;by\;\bf{12m.}}\\ \rm{Rate\;of\;carpeting=\bf{Rs\:4\:per\:sq.m.}}\end{cases}

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{\large{\underline{\bf{\maltese\:To\:Find:-}}}}

  • The cost of carpeting at the rate of Rs 4 per sq. m.

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\large{\underline{\bf{\maltese\:Solution:-}}}

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{\textit{\textbf{Finding\:Length\:and\:Breadth}}}

We know,

  • Length = breadth + 12 m.

and

  • Perimeter = 76 m.

So,

# Let breadth be x.

  • Length = x + 12

 \sf \mapsto  \: perimeter _{rectangle} = 2(length + breadth) \\  \\  \colon  \sf\implies \: \cancel{ 76} \: m = \cancel 2 \{(x + 12) + x \} \\  \\  \colon \sf \implies \: 38 \: m = 2x + 12 \\  \\  \colon \sf \implies \: 2x = 38 - 12 \\  \\  \colon \sf \implies \: \cancel 2x = \cancel{ 26} \\  \\  \longrightarrow \boxed{ \bf{x =  \pink{13 \: m}}}

So,

 \mapsto \sf \: breadth = x \: m \\  \\  \leadsto \:  \:  \underline{ \boxed{ \bf{ breadth =  \blue{13 \: m}}}}

And

 \sf \mapsto \: length = x + 12 \: m \\  \\   \mapsto \sf \: length = 13 + 12 \: m \\  \\ \leadsto \:  \underline{ \boxed{ \bf{length =  \purple{25 \: m}}}}

{\textit{\textbf{Finding\:the\:cost}}}

As we are carpeting the floor so ,

we have to first find the area of the floor.

We have :

  • Length = 25 m
  • Breadth = 13 m

 \mapsto \sf \: area _{rectangle} = length \times breadth \\  \\  \colon \implies \sf \: area = 25 \times 13 \:  {m}^{2}  \\  \\  \colon \implies \boxed{ \bf{ area =  \orange{325 \:  {m}^{2} }}}

Now ,

We know

  • Rate of carpeting = Rs 4 per m²

And,

 \star \longrightarrow \sf \: cost = area \times rate \\  \\  \tt \: so \\  \\  \colon \implies \sf \: cost = 325 \times 4 \\  \\  \colon \implies \underline{ \boxed{ \bf{ \red{cost = 1300 \: rs}}}}

Required Answer :

Cost of carpeting the Hall = 1300 Rs .

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