The length of hour hand of a wrist watch is 1.5 cm. Find magnitude tangential acceleration.
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The length of hour hand of a wrist watch is 1.5cm , r = 1.5cm = 0.015m
in case of uniform, circular motion, centripetal or angular acceleration = 0.
we know, tangential acceleration = radius of circular path × angular acceleration
= 0.015 × 0 = 0
hence, tangential acceleration = 0
in case of uniform, circular motion, centripetal or angular acceleration = 0.
we know, tangential acceleration = radius of circular path × angular acceleration
= 0.015 × 0 = 0
hence, tangential acceleration = 0
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HEY DEAR ... ✌️
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Here's , Your Answer ...
=) Given , length of hour hand of wrist watch (r) = 1.5 cm .
Now , Converting cm to m.
=) r = 1.5 cm
=) r = 0.015 m
To find :- Tangential acceleration .
We know , For circular motion , Angular momentum is zero .
Also , we know .
=) Tangential acceleration = Radius of circular path × Angular acceleration .
Now , putting the values.
=) 0.015 × 0
=) 0 ( answer)
Hence , The tangential acceleration is 0 .
_____________________
_____________________
HOPE , IT HELPS ... ✌️
__________________________
__________________________
Here's , Your Answer ...
=) Given , length of hour hand of wrist watch (r) = 1.5 cm .
Now , Converting cm to m.
=) r = 1.5 cm
=) r = 0.015 m
To find :- Tangential acceleration .
We know , For circular motion , Angular momentum is zero .
Also , we know .
=) Tangential acceleration = Radius of circular path × Angular acceleration .
Now , putting the values.
=) 0.015 × 0
=) 0 ( answer)
Hence , The tangential acceleration is 0 .
_____________________
_____________________
HOPE , IT HELPS ... ✌️
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