The length of kumar's rectangular field is 1½ times of its breadth , perimeter of the field is 400m.
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Answer:
Let,
the breadth of the field be x
therefore,
length = 1 ½ breadth
= 3/2 x
B/Q
perimeter = 400
=> 2 ( L + B ) = 400
=> 2 ( 3/2 x + x ) = 400
=> 2 ( (3x + 2x)/2 ) = 400
=> 2 ( 5x/2 ) = 400
=> 5x = 400
=> x = 400/5
=> x = 80
Therefore,
breadth = x = 80m
length = 3/2 x = 3/2 (80) = 120m
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