The length of line PQ is 10 units and the co-ordinates of P are(2,-3);calculate the co-ordinates of point Q,if its abcissa is 10.
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(10-2)^2+(y+3)^2=100
64+y^2+9+6y=100
y^2+6y+9=36
y^2+6y-27=0
y^2+9y-3y-27=0
y(y+9)-3(y+9)=0
y=-9. ,y=3
the point is Q(10,-9) or Q(10,3)
64+y^2+9+6y=100
y^2+6y+9=36
y^2+6y-27=0
y^2+9y-3y-27=0
y(y+9)-3(y+9)=0
y=-9. ,y=3
the point is Q(10,-9) or Q(10,3)
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