Question

the length of major axis of the ellipse 4x^2 + y^2 = 400 is​

Answer 1

cant get to your question

Answer 2

$\bold{Given: \: 4 {x}^{2} + {y}^{2} = 400 \: is \: equation \: of \: an \: ellipse.} \\ \bold{The \: standard \: form \: of \: equation \: of \: an \: ellipse \: is \: \frac{ {x}^{2} }{ {a}^{2} } + \frac{ {y}^{2} }{ {b}^{2} } = 1.} \\ \bold{So \: divide \: by \: 400.then} \\ \bold{ \frac{4 {x}^{2} }{400} + \frac{ {y}^{2} }{400} = \frac{400}{400}. } \\ \\ \bold{ \implies{ \frac{ {x}^{2} }{ (\sqrt{100} )^{2} } + \frac{ {y}^{2} }{ {( \sqrt{400} })^{2} } = 1.}} \\ \\ \bold{ \implies{ \frac{ {x}^{2} }{ (10 )^{2} } + \frac{ {y}^{2} }{ (20)^{2} } = 1.}} \\ \bold{Now \: it \: seems \: like \: the \: standard \: form \: of \: equation \: of \: an \: ellipse. \: so \:compare \: with \: standard \: form \: of \: equation. \: then } \\ \bold{a = 10 \: and \:b \: = 20. \: \therefore{major \: axis \: will \: be \: 20 \: units.}}$