Math, asked by priya6386, 1 year ago


The length of metallic pipe is 70cm Inner diameter is
10 cm and thickness is 5 mm. density of
Metal used is 8g /cm, then find the mass of the pipe

Answers

Answered by GodBrainly
13

\\ \blue{\huge{\underline{\overline{\mid{\bold{\purple{ \: \:  \: Solution: \: \: \:  \blue{\mid}}}}}}}} \\  \\   \\  \\ \bf Length= 70  \: cm \\   \\ \bf</p><p></p><p>I nner \:  diameter= 10 \:  cm</p><p> \\  \\  \bf</p><p>I nner \:  radius= 5 \: cm \\  \\ </p><p> \bf</p><p>T hickness=5 \: mm \\  \bf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: =0.5 \: cm</p><p> \\ \\   \bf</p><p>Outer \:  radius= inner \:  radius + thickness \\ \\   \bf</p><p></p><p>Volume \:  of \:  Cylinder= π(outer  \: radius)(height)  \\  \bf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \: </p><p></p><p>= \frac{22}{7}  \times 5.5 \times 70 \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \: </p><p> \bf= 6650 \: cm {}^{3} \\ \\   \bf </p><p>Density=  \frac{Mass}{Volume}  \\  \bf</p><p></p><p>Density \times Volume=Mass \\  \bf</p><p></p><p>8 \times 6650= mass \\  \bf</p><p> Mass</p><p>=53240g</p><p></p><p>


priya6386: thanks ❤️❤️
Answered by Anonymous
10

step \: by \: step \: eplanatation \\  \:   \:   \\ Diameter  \: of  \: the \:  outer \:   \: circle \:  \ is  \: 70 \: cm </p><p> \\ </p><p>Radius  \: of \:  the \:  outer \:  circle \:  \:   \:is  \: 70/2 = 35 \\ </p><p></p><p>Given  \: Thickness \:  is = 10 cm</p><p></p><p> \\ Radius  \: of  \: the \:  inner \:  circle = </p><p></p><p>r =  - 10 = 25 \:  \\  length \: of \: the \: pipe = 5m =  500cm \\ hence \: volume \: of \: the \: pipe \: \pi \: r ^{2}h \:  - \pi \: r ^{2}h \\ \pi \: h( {r}^{2}  - r ^{2} ) \\ \pi h(r + r)(r - r) \\ 3.14 \times 500(35 + 25)(35 - 25) \\ 3.14 \times 500  \times 60 \times 10 \\ v  = 942478 \: cm ^{3} \\ given \: density \: of \: metal \: 8g |cm^{3}  \\ we \: know \: that  \: mass \: is \: defined as \: the \: product \: of \: volume \: and \: density \:  \\ mass \:  = volume \times density \\ 942478 \times 8 = 7539824 \: grams \\

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