Question

The length of minute hand of a clock is 14cm. find area swept by minute hand in 10 min​

Answer 1

Answer:

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Let the length of the minute hand be the clock's radius = 14 cm

Area swept by minute hand in 10 minutes = 10 times the area of the circle

Area of the circle = $\pi {r}^{2}$

Area swept by minute hand in 10 min. = $10 \times \frac{22}{7} \times {14}^{2} = 6160 {cm}^{2}$

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Answer 2

Answer:

Explanation:

Area swept by the minute hand = theta/ 360 ×π×14×14= 308/3= 102.5