The length of minute hand of a clock is 21 cm. The area swept by the minute hand in 10 minute is
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Answer:
One revolution of the minutes hand of a clock of 21 cm length of represents a circle with 21 cm radius.
The area of full circle is πr^2
= 22/7 x 21 x 21 = 22 x 3 x 21 = 1386 sqcm
The minutes hand covers an angle of 6° per minute. So, it covers an angle of 60° in 10 minutes.
Area swept in 10 minutes :
= 1386 x 60/360
= 231 sqcm
Step-by-step explanation:
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r = 21Area swept in 1 minute is 6degrees
Area swept in 10 minutes is 60 degrees
area = thetadiv 360 times pi times{r^{2}
area=θ÷360×pi×r^2
area = 60div360 times (22 div 7) times 21 times 21
area=60÷360×(22÷7)×21×21area = 231 {cm}^{2}
area=231cm2
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