the length of one diagonal of a rhombus is less than the second diagonal by 4cm. the area of the rhombus is 30sq.cm. find the length of the diagonal
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Area = 30 sq. Cm
1 diag. =x
2 diag.=x+4
So,
30=1/2*x*x+4
=1/2*2x+4
=2x/2+4
30=x+4
30-4=x
26=x
1 diag. =x
2 diag.=x+4
So,
30=1/2*x*x+4
=1/2*2x+4
=2x/2+4
30=x+4
30-4=x
26=x
kaushikee:
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