the length of one diagonal of a rhombus is less than the second diagonal by 4cm the area of the rhombus is 30 sq.cm find the length of the diagonals
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let diagonal be x and x-4
area =d1×d2/2
30=(X×X-4)/2
30×2=x^2-4x
60=x^2-4x
area =d1×d2/2
30=(X×X-4)/2
30×2=x^2-4x
60=x^2-4x
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