Question

The length of one of the diagonals of a field, which
is in the shape of a quadrilateral, is 40 m. The
perpendicular distances of the other two vertices
from the diagonal are 12 m and 9 m. Find the area
of the field.​

Answer 1

Step-by-step explanation:

$\huge\bf\star\fbox\red{Answer:-}$

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$\Large\bf\star\fbox\red{Given:-}$

$\mapsto$ $\bf\fbox\purple{d\ =\ 40m}$

$\mapsto$ $\bf\fbox\purple(h_1 = 12m)$

$\mapsto$ $\bf\fbox\purple(h_2 = 9m)$

$\Large\bf\star\fbox\red{We\ know\ that:-}$

$\mapsto$ $\bf\fbox\green{Area\ of\ quadilateral} = \dfrac{1}{2}d (h_1 + h_2)$

$\mapsto$ $\dfrac{1}{2} × 40 (12 + 9) = 20 × 21 = 420m²$

$\bf\star\fbox\purple{Hence,\ it\ is\ the\ required\ answer}\star$

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$\Large\bf\star\fbox\red{Hope\ it\ helps\ you}\star$