Question

the length of one side of a rhombus is 41 cm and its area is 720 CM square what is the sum of the length of its diagonal calculate

Answer 1

Refer to the attached image.

Given: A rhombus ABCD with each side as 41 cm. So, AB = AD = BC = CD = 41 cm

Since, diagonals of rhombus bisect each other at right angle.

Let AO = OC = OB = OD = 'x' cm

Consider triangle AOB,

By Pythagoras theorem, we get

$AB^2 = OA^2 + OB^2$

$41^2 = x^2 + x^2$

$1681= 2x^2$

$x = 28.99$

So, x = 29 cm

Therefore, length of diagonal = x+ x = 29+29 = 58 cm.