Question

the length of one side of a right triangle is 24 cm an the length of its hypotemuse is 40 cm. Find the length of its third side. ​

Answer 1

${\large{\mathfrak{\blue{\underline{\red{Solution:}}}}}}$

According to pythagonas therom,

${\boxed{\pink{\sf{ {Hypotenuse}^{2} = {Perpendicular}^{2} + {Base}^{2} }}}}$

So, putting the values given in question:

$\purple{\rightarrow}$ H² = P² + B²

$\purple{\rightarrow}$40² = 24² + B²

$\purple{\rightarrow}$1600 = 576 + B²

$\purple{\rightarrow}$1600 - 576 = B²

$\purple{\rightarrow}$1024 = B²

$\purple{\rightarrow}$√1024 = B

$\purple{\rightarrow}$32 = B

Therefore, the length of the third side = 32 cm.

Answer 2

Answer:

1. let the third side be x^
2. 40^2=24^2 +x^2
3. 1600=576+x^2
4. x^2=1600-576
5. x^2=1024
6. √x=√1024
7. x=32