Question

The length of one side of a square is increased by 1 cm and that of the other side is reduced by 3 cm.
The rectangle now formed has a perimeter of 64 cm
What is the length of the side of the original square?​

Answer 1

Answer:

Let the side of square be x ,length and breadth of rectangle will be x +1 and x-3

perimeter of rectangle = 2 ( l+b )

64 {2(x+1 + x-3)

32- 2×-2

x= 17

Step-by-step explanation:

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Answer 2

$\Huge{\textbf{\textsf{{\color{navy}{an}}{\purple{sw}}{\pink{er}}{\color{pink}{:}}}}}$

$\large\bf{{\underline{To~find}}:}$

$\sf The \: length \: of \: the \: square$

$\bf{Perimeter~of~a~rectangle:}$

$\sf{~~~~~~~~~~2(l+b)}$

$\sf{Let~the~length~of~the~square~be~‛x’~cm}$

$\bf{Here;}$

$\sf{~~~~~~~~~~l=x+1~~,~~~~b=x-3}$

$\sf{:→ 2[~(x+1)+(x-3)~]=64cm}$

$\sf{:→ 2(2x-2)=64}$

$\sf{:→ 4x-4=64}$

$\sf{:→ 4x=64-4}$

$\sf{:→ 4x=60}$

$\sf{:→ x={\dfrac{60}{4}}}$

$\sf{:→ x=\color{blue}{\underline{\boxed{\bf 15cm}}}}$

$\bf\therefore{Length~of~the~square:}$

$\Large\bf{~~~~~{\underline{\underline{15cm}}}~~~~~{\color{blue}{✓}}}$