*The length of one side of the rectangle is twice the length of its adjacent side. If the
perimeter of rectangle is 60 cms, find the area of the rectangle.
Answers
Answered by
22
Given: Length of the rectangle is twice the length of its breadth and the perimeter is 60cm.
To find: The area.
Answer:
Let the breadth be x.
Therefore length = 2x (Since length is twice the breadth)
Formula to find perimeter:
Perimeter = 2(Length + Breadth)
Substituting the given values,
60 = 2(2x + x)
60 = 2*3x
60 = 6x
x = 60/6
x = 10cm
Therefore length = 2*10 = 20.
Formula to find area:
Area = Length*Breadth
Substituting the given values,
Area = 20*10
Area = 200cm^2
Hope it helps :)
Answered by
7
let the breath of rectangle be a
then length of rectangle be 2a
perimeter of rectangle = 2 (l+b )
60 = 2 (2a + a )
60/2 = 3a
30 = 3a
30/3 = a
a= 10 cm
length of rectangle = 2a= 2(10) = 20cm
breath of rectangle = a = 10 cm
area of rectangle= l × b
= 20× 10
= 200 cm ^2
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then length of rectangle be 2a
perimeter of rectangle = 2 (l+b )
60 = 2 (2a + a )
60/2 = 3a
30 = 3a
30/3 = a
a= 10 cm
length of rectangle = 2a= 2(10) = 20cm
breath of rectangle = a = 10 cm
area of rectangle= l × b
= 20× 10
= 200 cm ^2
plz mark as brainlist ✌️✌️
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