Question

the length of one string is 4 metres and the length of another string is 14 metres​

Answer 1

Answer:

et L is the original length of the wire and k is force constant of wire.

Final length = initial length + elongation

L

′

=L+

k

F

For first condition a=L+

k

4

.....(i)

For second condition b=L+

k

5

......(ii)

By solving Eqs. (i) and (ii), we get

L=5a−4b and k=

b−a

1

Now, when the longitudinal tension is 9N. length of the string.

=L+

k

9

=5a−4b+9(b−a)

=5b−4a