Question

The length of parallel sides of a trapezium are 24cm and 40cm.If the distance between them is 12cm find the area of trapezium.​

Answer 1

Answer:

By data, it's an isosceles trapezium. Altitude is not provided. On either side, a right triangle can be constructed, with 12 cm hypotenuse and one leg 6 cm.

By Pythagoras theorem,

Altitude, h = √(12²-6²) = √(12+6)(12–6) = √(18)(6) = √108 = 6√3

Area(trapezium) = ½(28+40)(6√3) = 68×3√3 = 204√3 cm

Answer 2

,

Step-by-step explanation:

the answer is 128cm sq

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