the length of parallel sides of a trapezium are 24cm and 40cm. if the distance between them is 12cm find the area of trapezium
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Step-by-step explanation:
By data, it's an isosceles trapezium. Altitude is not provided. On either side, a right triangle can be constructed, with 12 cm hypotenuse and one leg 6 cm.
By Pythagoras theorem,
Altitude, h = √(12²-6²) = √(12+6)(12–6) = √(18)(6) = √108 = 6√3
Area(trapezium) = ½(28+40)(6√3) = 68×3√3 = 204√3 cm
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