Question

The length of parallel sides of a trapezium are (x+8) cm and (2x+3) cm , and the distance between them is (x+4)cm . Its area is 590cm square , find the value of x .

Answer 1

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Answer 2

The value of x is 16

Step-by-step explanation:

The length of parallel sides of a trapezium are (x+8) cm and (2x+3) cm

The distance between them is (x+4)cm .

Area of trapezium = $\frac{1}{2}(\text{Sum of parallel sides}) \times Height$

Area of trapezium =$\frac{1}{2}(x+8+2x+3)(x+4)$

We are given that its area is 590cm square

So, $590= \frac{1}{2}(x+8+2x+3)(x+4)$

$590 \times 2 =(3x+11)(x+4)\\1180=3x^2+12x+11x+44\\x=\frac{-71}{3},16$

Since Side cannot be negative.

So, The value of x is 16

#Learn more:

The length of parallel sides of a trapezium are (x+8) cm and (2x+3) cm , and the distance between them is (x+4)cm . Its area is 590cm square , find the value of x .

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