Question

The length of parallel sides of an isosceles trapezium are 6 cm and 14cm. The length of each

non-parallel sides is 5 cm. Find the area of trapezium.​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

50 cm²

Step-by-step explanation:

$area \: of \: trapezium = \frac{1}{2} (sum \: of \: parallel \: side) \times height$

so

$area = \frac{1}{2} \times (6 + 14) \times 5 \\ = \frac{1}{2} \times (20) \times 5 \\ = 10 \times 5 \\ = 50 {cm}^{2}$

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