the length of parallel sides of isosceles trapezium are 6cm and 14cm. the length of each non parallel sides is 5cm. find the area of trapizium
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Answer:-
Let us consider a trapezium ABCD with 2 non parallel sides AB =CD = 5cm and 2 parallel sides BC = 6cm and AD = 14cm . Then when 2 non parallel sides are of equal length then parallel sides will be of formation such that when a bisector is drawn through one side it even bisects the other side .So , when we draw a perpendicular through B to AD or C to AD then we can get the perpendicular height 'h' = AL.
Now since AB and CD are equal AD will be equally distributed on both sides of BC so (14 - 6)/2 = 4cm = BL on both sides of BC .
Then by using Pythagoras theorerm,
=> AB² = AL² + BL²
=> 25 = h² + 16
=> h = 9cm
Then height of trapezium, h = 9cm
Step-by-step explanation:-
Now let us apply the formula for area of trapezium,
=> A = h(a+b)/2
=> A = 9(6+14)/2
=> A = 9*10
=> A = 90square cm
Hence , the area of the trapezium ABCD is 90square cm.
THANK YOU FOR THE WONDERFUL QUESTION...
#bebrainly
HOPE THIS HELPS YOU...
Answer:-
Let us consider a trapezium ABCD with 2 non parallel sides AB =CD = 5cm and 2 parallel sides BC = 6cm and AD = 14cm . Then when 2 non parallel sides are of equal length then parallel sides will be of formation such that when a bisector is drawn through one side it even bisects the other side .So , when we draw a perpendicular through B to AD or C to AD then we can get the perpendicular height 'h' = AL.
Now since AB and CD are equal AD will be equally distributed on both sides of BC so (14 - 6)/2 = 4cm = BL on both sides of BC .
Then by using Pythagoras theorerm,
=> AB² = AL² + BL²
=> 25 = h² + 16
=> h = 9cm
Then height of trapezium, h = 9cm
Step-by-step explanation:-
Now let us apply the formula for area of trapezium,
=> A = h(a+b)/2
=> A = 9(6+14)/2
=> A = 9*10
=> A = 90square cm
Hence , the area of the trapezium ABCD is 90square cm.
THANK YOU FOR THE WONDERFUL QUESTION...
#bebrainly
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