Question

The Length of parallel sides of trapezium is 12 cm and 8 cm and its height is 5 cm. find area​

Answer 1

Answer:

h=5

Step-by-step explanation:

This looks like a math homework question. I will solve your initial problem but using the sides 4, 8 and Area 30 instead.

Area formula for a trapezium (a.k.a trapezoid):

A=b1+b22h

Where A is the total area, b1 and b2 are the parallell sides of the trapezoid, and h is the height of the trapezoid. And we want to know what? Right, the height, or h . So, let’s rewrite the formula:

A=b1+b22h

2A=(b1+b2)h

2Ab1+b2=h

Now let us look at what is known:

A=30

b1=4

b2=8

Finally, insert the numbers:

2⋅304+8=6012=5

Answer: h=5

There you go. Everything you need to solve your particular problem. Now solve it! :)

Answer 2

Given :-

• Length of the parallel sides of a trapezium = 12cm and 8cm respectively
• Height of the trapezium = 5cm

Aim :-

• To find the area of the trapezium

Answer :-

Formula to use :-

$\boxed {\sf \longrightarrow Area \: of \: a \: trapezium = \frac{1}{2} \times height \: (sum \: of \: parallel \: sides)}$

Substituting the values,

$\implies \sf \dfrac{1}{2} \times5 \times (12 + 8)$

Adding the numbers inside the brackets,

$\implies \sf \dfrac{1}{2} \times 5 \times 20$

Cancelling, 2 and 20 (as 20 is exactly divisible by 2),

$\implies \sf 5 \times 10$

$\implies \sf 50 {cm}^{2}$

Therefore the area of the trapezium is 50cm².

Some more formulas :-

$\boxed{ \sf \longrightarrow Area \: of \: a \: triangle = \dfrac{1}{2} \times base \times height}$

$\boxed {\sf \longrightarrow Area \: of \: a \: square = side \times side \to {side}^{2} }$

$\boxed {\sf \longrightarrow Area \: of \: a \: rectangle \: = length \times breadth}$

$\boxed {\sf \longrightarrow Area \: of \: a \: parallelogram = base \times height}$

$\boxed {\sf \longrightarrow Area \: of \: a \: rhombus = \dfrac{1}{2} \times diagonal _{1} \times diagonal_{2}}$