Question

The length of pendulum is decreased by 10% . What is change in frequency?​

Answer 1

Answer:

T = 2 π sqrt(L / g) = 1/f

f^2 ∝ 1/L

(f1/f2)^2 = (L2/L1)

[(100) / (100 + x)]^2 = (90 / 100)

(100 + x)^2 = (10000 / 0.9)

100 + x = 105.4

x = 105.4 - 100

x = 5.4

Frequency will increase by 5.4%

Answer 2

Answer:

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