Question

the length of perpendicular from (4,3) to the straight line which makes intercepts 4,3 on co ordinate axes is ​

Answer 1

Hope this will help you!!!

Answer 2

Answer:

$\displaystyle \sf{{\rightarrow \frac{12}{5} \ units}}$

Step-by-step explanation:

Given :

Slope 4 and 3

a = 4 and b = 3

We have slope intercept form :

i.e. x / a + y / b = 1

Putting given intercept we get :

x / 4 + y / 3 = 1

3 x + 4 y = 12

3 x + 4 y - 12 = 0

Now length of perpendicular :

$\displaystyle \sf{{d=\left|\frac{ax_1+by_1+c}{\sqrt{a^2+b^2}} \right| }}$

We have :

a = 4 and b = 3

x₁  = 3 , y₁ = 4 and c = - 12

$\displaystyle \sf{{d=\left|\frac{3\times4+4\times3-12}{\sqrt{4^2+3^2}} \right| }} \\\\\\\displaystyle \sf{{d=\left|\frac{12}{5} \right|}}\\\\\\\displaystyle \sf{{d=\frac{12}{5} \ unit}}$

Therefore we get answer.