Question

the length of rectangle exceeds its breadth a by 3 cm. Its area is (121+3a)sqcm then the length of rectangle is
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Answer 1

Step-by-step explanation:

Let the breadth be a cm

Then length will be (a + 3) cm

We know that,

Area of the rectangle = l × b

⟹ 121 + 3a = (a) × (a+ 3)

⟹ 121 + 3a = a² + 3a

⟹ 121 + 3a - 3a = a²

⟹ 121 = a²

⟹ a = √121

⟹ a = 11

Hence,

Breadth = a = 11 cm.

length = a + 3 = 14 cm.

Answer 2

Given:

area is (121+3a)cm²

the length of rectangle exceeds its breadth a by 3 cm.

Let the breadth be a cm

Then length will bel= (a + 3) cm

are of rectangle = (121+3a)cm²

We know that,

Area of the rectangle = l × b

121 + 3a = (a) × (a+ 3)

121 + 3a = a² + 3a

121 + 3a - 3a = a²

121 = a²

 a = √121

 a = 11

Breadth = a = 11 cm.

length = a + 3 = 14 cm.

Hence the length is 14 cm