the length of rectangle exceeds its breadth by 12 metres if the perimeter is 152 mt then find its dimensions
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13 is the answer of this is that simple
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Let Breadth of Rectangle be x
- Then Length will be x + 12
Perimeter of Rectangle = 2(Length + Breadth)
⇒ Perimeter of Rectangle = 2(x + x + 12)
⇒ 152 m = 2(x + x + 12)
⇒ 152 m = 2(2x + 12)
⇒ 152 m = 4x + 24
⇒ 152 m - 24 = 4x + 24 - 24
⇒ 128 = 4x
⇒ 4x = 128
⇒ x = 128/4
⇒ x = 32 m
- Breadth = x = 32 m
- Length = x + 12 = 32 + 12 = 44 m
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