the length of rectangle exceeds its breadth by 14 cm if the length is decreased by 8 cm and breadth is increased by 6 and the area of both is same find the length and breadth
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Given:-
- The length of rectangle exceeds its breadth by 14 cm
- if the length is decreased by 8 cm and breadth is increased by 6 and the area of both is same
To Find:-
- The Length and Breadth of Rectangle
Formulae used:-
- Area of Rectangle = L × B
Now,
Let the Breadth be "x"
→ Length of Rectangle = x + 14
→ Area of Original Rectangle = L × B
→Area of Original Rectangle =(x) ( x + 14) → x² + 14x
Now, Atq
→ Length of New Rectangle = x + 14 - 8→ x + 6
→ Breadth of New Rectangle = x + 6
→ Area of New Rectangle = L × B → ( x + 6) ( x + 6)
→ Area of New Rectangle = x² + 12x + 36.
But, it also given that area of both rectangle is same.
→ x² + 14x = x² + 12x + 36
→ 14x = 12x + 36
→ 14x - 12x = 36
→ 2x = 36
→ x = 36/2
→ x = 18
Therefore,
→ Breadth of Original Rectangle = 18cm
→ Length of Original Rectangle = x + 14→ 32
Hence, The length and Breadth of Rectangle is 18 and 32 respectively.
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