The length of rectangle exceeds its breadth by 5 centimetre two vertices of a triangle coincide with that of the rectangle and third vertex lies on the opposite side of the rectangle. then what will be area of the remaining part .
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B =x
L= x+7
Original Area =x×(x×7)=x^2+7x
New length =x+7-4=x+3
New breadth =x+3
New area =(x+3)(x+3)=x^2+6x+9
A2Q
=x^2+7x =x^2+6x+9
=x^2- x^2+7x=6x+9
=7x-6x=9
=x=9cm=Breadth
9+7=16cm=Length
Omjeeb:
please read the question carefully
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