The length of rectangle exceeds its breadth by 8cm and the area of rectangle is 240 sq cm find the diameter
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How can one find the diameter of a rectangle
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let breadth = x cm
length = (x+8) cm
x(x+8)= 240
x^2+8x-240= 0
x^2+20x-12x-240=0
x(x+20)-12(x+20) = 0
(x+20)(x-12)=0
x = 12 cm
x+8 = 20cm
Perimeter = 2(20+12) = 64cm
length = (x+8) cm
x(x+8)= 240
x^2+8x-240= 0
x^2+20x-12x-240=0
x(x+20)-12(x+20) = 0
(x+20)(x-12)=0
x = 12 cm
x+8 = 20cm
Perimeter = 2(20+12) = 64cm
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