Question

the length of rectangle exceeds its width by 2m if perimeter is 20m ,find the dimension.​

Answer 1

Answer :-

The Rectangle's Length is 6 m and its Breadth is 4 m.

Explanation :-

Given :

Length of the Rectangle exceeds it's width by 2 m

Perimeter of the Rectangle = 20 m

To Find :

Its Dimensions

Solution :

Consider the -

• Width as x
• Length as (x + 2)

★ Perimeter = $\boxed{\sf{2(Length+Breadth)}}$

$\sf{\longrightarrow} \:2(x + x + 2) = 20$

$\sf{\longrightarrow} \:2x + 2x + 4 = 20$

$\sf{\longrightarrow} \:4x = 20 - 4$

$\sf{\longrightarrow} \:4x = 16$

$\sf{\longrightarrow} \:x = \dfrac{16}{4}$

$\sf{\longrightarrow} \:x = 4$

$\rule{300}{1.5}$

★ Value of (x + 2)

$\sf{\longrightarrow} \:4 + 2$

$\sf{\longrightarrow} \:6$

$\therefore$ The Rectangle's Length is 6 m and its Breadth is 4 m.

Answer 2

Answer:

☆The length of rectangle exceeds its width by 2m.

☆Perimeter is 20 m .

●To find:

Dimension .

♤Solution :

Suppose ,

■The width = x

■The length (x + 2)

♤ Formula of perimeter :

2(Length + Breadth)

2(x + x + 2)= 20

2x + 2x + 4 = 20

4x = 20 - 4

x= 16

4

x= 4

Value of ( x + 2 )

4 + 2

= 6

So,

The length of rectangle = 6m

The breadth of rectangle = 4m .

Thanks .