Question

The length of rectangle exceeds twice its breadth by 2 cm. if the perimeter of rectangle is 28 cm, find its length and breadth​

Answer 1

$\mathfrak{\large{\underline{\underline{Answer :-}}}}$

The Length is 10 cm and Breadth is 4 cm.

$\mathfrak{\large{\underline{\underline{Explanation :-}}}}$

Given :

Length of the Rectangle = exceeds twice its breadth by 2 cm

Perimeter of the Rectangle = 28 cm

To Find :

The Length and Breadth

Solution :

◆ $\textbf{\small{\underline{Consider the - }}}$

• Breadth as x
• Length as (2x + 2)

★ Perimeter = $\boxed{\sf{2(Length+Breadth)}}$

$\longrightarrow$ 2(x + 2x + 2) = 28

$\longrightarrow$ 2x + 4x + 4 = 28

$\longrightarrow$ 6x + 4 = 28

$\longrightarrow$ 6x = 28 - 4

$\longrightarrow$ 6x = 24

$\longrightarrow$ x = 24/6

$\longrightarrow$ x = 4

Breadth = 4 cm

$\rule{300}{1.5}$

★ Value of (2x + 2)

$\longrightarrow$ 2(4) + 2

$\longrightarrow$ 8 + 2

$\longrightarrow$ 10

Length = 10 cm

$\therefore$ The Length is 10 cm and Breadth is 4 cm.

Answer 2

Answer :

The  Breadth is 4 and Length is 10 cm.

Step-by-step explanation :

Given that :

Perimeter of the Rectangle = 28 cm.

Length of the Rectangle = exceeds twice its breadth by 2 cm.

To Find :

The Breadth  and Length .

Solution :

Let the Breadth =  x  and  Length =  (2y + 2)

We know that :

★Perimeter :

$\boxed{\sf{2(Length+Breadth)}}$

Put values :

$\tt \longrightarrow 2(x + 2y + 2) = 28\\ \\\longrightarrow 2x + 4y + 4 = 28 \\ \\\longrightarrow 6x + 4 = 28\\ \\ \longrightarrow 6x = 28 - 4\\ \\\longrightarrow 6x = 24\\ \\\longrightarrow x = \dfrac{24}{6}\\ \\\longrightarrow x = 4$

Hence, Breadth = 4 cm.

Now,

Length =  (2y + 2)

So,

$\tt \longrightarrow 2(4) + 2\\ \\\longrightarrow 8 + 2\\ \\\longrightarrow 10 \\ \\ \\\\\star \textbf{\underline{\underline{The Length is 10 cm and Breadth is 4 cm}}}$