Question

the length of rectangle is 10 m
more than its breadth of the
perimeter of rectangle is 80m
find dimensions of rectangle​

Answer 1

Answer:

Step-by-step explanation:

Explanation:

The perimeter of an object is the sum of all it's lengths. So in this problem, 80m = side1 + side2 + side3 + side4.

Now a rectangle has 2 sets of equal length sides.

So 80m = 2xSide1 + 2xSide2

And we are told that the length is 10m more than it's breadth.

So 80m = 2xSide1+(10+10) + 2xSide2

So 80m = 2xS1+20 +2S2

80 = 2x + 2y + 20

If it were a square, x + y would be the same

so

60 = 4x side1

so side 1 = 60/4 = 15m

So side 1 = 15m, side 2 = 15m, side 3 = 15m+10m side 4 = 15+10m

So s1 = 15m, s2 = 15m, s3 = 25m, s4 = 25m.

Perimiter = 80m and the length of th e rectangle is 10m longer than the breadth

Answer 2

Given:

Length of a rectangle is 10 m more than it's Breadth.

Perimeter of the rectangle is 80 m.

To Find:

The dimensions of the rectangle.

i.e. Length and Breadth

Assumption:

Breadth = x

Length = x + 10

Formula:

Perimeter = 2 ( l + b )

Solution:

By putting the Assumed values of Length and Breadth, we get

2 ( x + 10 + x ) = 80

By opening the brackets, we get

2x + 20 + 2x = 80

or, 4x + 20 = 80

By taking 20 to the LHS, we get

4x = 80 - 20

or, 4x = 60

By taking 4 to the LHS, we get

$\huge \rm {x = \frac {60}{4}}$

$\huge \rm {or, \: x = 15}$

ANSWER :

Length = x + 10

Length = 15 + 10

Length = 25 m

Breadth = 15 m