Question

The length of rectangle is 12 cm and its diagonal is 13 cm.Find its perimeter.

Answer 1

Answer:

The perimeter of the rectangle is 34 cm

Step-by-step explanation:

• Let ABCD be the rectangle whose length is 12 cm,diagonal is 13 cm.
• Now we know that all angles of arectangle are right angles.So,we can use pythagoras theorem to find the breadth.
• So,applying pythagoras theorem,

(hypotenuse)^2=(perpendicular)^2+(base)^2 =>13^2=(perpendicular)^2+12^2 => (perpendicular)^2=13^2-12^2 => (perpendicular)^2=(13+12)(13-12)[a^2-b^2=(a+b)(a-b)] => (perpendicular)^2= 25×1 =>(perpendicular)^2=25 =>(perpendicular)=25^1/2 =>(perpendicular)=5. So,the breadth of the rectangle is 5cm.

Now perimeter of the rectangle=2(l+b) =>perimeter=2(12+5)

=>perimeter=2×17

=>perimeter=34.

So,the perimeter of this rectangle is 34 cm.

Answer 2

Answer:

Above is correct