The length of rectangle is 20℅ more than its breadth. What will be the ratio of the area of a rectangle to that of a square whose side is equal to the breadth of the rectangle?
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Step-by-step explanation:
Let the breadth of rectangle be x
The length of a rectangle is 20% more than its breadthLength = 20/100x + x = 0.2x + x = 1.2x
Area of rectangle = Length × Breadth
Area of rectangle = 1.2x
= 1.2x square
Side of square = Breadth of rectangle = x
Side of square = Breadth of rectangle = xSo, area of square = Side square = x square
Now the ratio of the area of a rectangle to that of a square = 1.2x square/ x square
= 12/10
= 6/5
Hence the ratio of the area of a rectangle to that of a square is 6:5
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