The length of rectangle is 3 more than its breadth if perimetre is 30 then its length is
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Answered by
0
let, length be 3+b
breadth be b
perimeter be 30+3+b
now,
perimeter of rectangle=2(l+b)
30+3+b=2(3+b+b)
33+b=2(3+2b)
33+b=6+4b
33-6=4b-b
27=3b
27/3=b
9=b
so, breadth of rectangle=b
=9
length of rectangle=3+b
=3+9
=12
perimeter of rectangle=30+3+b
=30+3+9
=42
breadth be b
perimeter be 30+3+b
now,
perimeter of rectangle=2(l+b)
30+3+b=2(3+b+b)
33+b=2(3+2b)
33+b=6+4b
33-6=4b-b
27=3b
27/3=b
9=b
so, breadth of rectangle=b
=9
length of rectangle=3+b
=3+9
=12
perimeter of rectangle=30+3+b
=30+3+9
=42
Answered by
0
let breadth be = x
length = x + 3
perimeter = 2( l +b)
according to the question
2 ( x + x +3) = 30
2( 2x + 3) = 30
4x + 6 = 30
4x = 30-6
4x = 24
x = 24/4 = 6
length = x+ 3
= 6+ 3
=9
hope it helps you.
PLEASE MARK ME AS BRAINLIEST.
length = x + 3
perimeter = 2( l +b)
according to the question
2 ( x + x +3) = 30
2( 2x + 3) = 30
4x + 6 = 30
4x = 30-6
4x = 24
x = 24/4 = 6
length = x+ 3
= 6+ 3
=9
hope it helps you.
PLEASE MARK ME AS BRAINLIEST.
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