Math, asked by periwinkle37, 5 months ago


The length of rectangle is 4cm and breadth is 300 cm . Find its area and perimeter .​

Answers

Answered by guptaamitx
0

Answer:

Area= 1200cm²

Perimeter= 608cm

Step-by-step explanation:

Length= 4cm

Breadth= 300cm

Area= length×breadth

= 4×300

= 1200cm²

Perimeter= 2(length+breadth)

=2(4+300)

= 2×304

= 608cm

Hope It Helps :)

Answered by Anonymous
4

\boxed{\huge{\bf{\star{Correct\:question \:-:}}}}

  • The length of rectangle is 4cm and breadth is 300 cm . Find its area and perimeter .

\huge{\bf{AnswEr -:}}

  • \boxed{\sf{\purple{Perimeter \:of \: Rectangle \: =\:608 cm}}}
  • \boxed{\sf{\purple{Area \:of \: Rectangle \: =\:1200 cm²}}}

Explanation-:

\huge{\bf{Given -:}}

  • The length of rectangle is 4cm .
  • The breadth of rectangle is 300 cm .

\huge{\bf{To \: Find ,}}

  • Area of a Rectangle.
  • Perimeter of a Rectangle.

\huge{\bf{Solution,}}

  • \boxed{\sf{\purple{Area \:of \: Rectangle \: =\:Length \times \: Breadth}}}

Here ,

  • The length of rectangle is 4cm .
  • The breadth of rectangle is 300 cm .

Now,

\large{\sf{\Rightarrow{\pink{ Area \: of \:Rectangle \: = 4 \times 300 }}}}

\large{\sf{\Rightarrow{\pink{ Area \: of \:Rectangle \: = 1200 cm ²}}}}

Therefore,

  • \boxed{\sf{\purple{Area \:of \: Rectangle \: =\:1200 cm²}}}

NOW ,

  • \boxed{\sf{\purple{Perimeter \:of \: Rectangle \: =2×(\:Length + \: Breadth)}}}

Here ,

  • The length of rectangle is 4 cm .
  • The breadth of rectangle is 300 cm .

Now ,

\boxed{\sf{\pink{Perimeter \:of \: Rectangle \: =2×(\:3 + \: 300)}}}

\boxed{\sf{\pink{Perimeter \:of \: Rectangle \: =2×(304)}}}

\boxed{\sf{\pink{Perimeter \:of \: Rectangle \: =608 cm }}}

Therefore,

  • \boxed{\sf{\purple{Perimeter \:of \: Rectangle \: =\:608 cm}}}

Hence ,

  • \boxed{\sf{\purple{Perimeter \:of \: Rectangle \: =\:608 cm}}}
  • \boxed{\sf{\purple{Area \:of \: Rectangle \: =\:1200 cm²}}}

________♡____________

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