The length of rectangle is 4times it's width twice the perimeter of the rectangle is 160cms find the length and width of rext
Answers
Answer:
width of the rectangle= 16 cm
Length of rectangle=4x= 64 cm
Step-by-step explanation:
Let the width of the rectangle be x cm
Therefore, Length of rectangle = 4x cm
Perimeter of rectangle = 160 cm ( given)
2( l + b) = 160
( 4x + x) = 80
5x= 80
x= 16 cm
Therefore, width of the rectangle= 16 cm
Length of rectangle=4x= 64 cm
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Answer:
Length of the rext=32 cm
Length of the rext=32 cmwidth of the rext=8cm
Step-by-step explanation:
Given:-
The length of rectangle is 4times it's width twice the perimeter of the rectangle is 160cms
To find:-
find the length and width of rext
Solution:-
Let the width of the rectangular rext be X cm
Then, the length=4 times it's width=4X cm
perimeter of the rectangle =2(l+b) units
= P=2(4X+X)cm
=>P=2(5X)cm
=>P=10X cm
According to the given problem
Twice the perimeter=160cm
=>Perimeter=160/2
=>Perimeter=80cm
=>10X=80
=>X=80/10
=>X=8
Length=4X=4×8=32 cm
Width=X=8cm