Question

The length of rectangle is 5cm more than its width and the area is 50cm find the length of a rectangle

Answer 1

Step-by-step explanation:

Then length =5+x

Area=lengthxbreadth=50 cm²

x(5+x)=50

x²+5x-50=0 on solving x=5 or x=-10

x can't be -ve so x=5

Width=x=5cm

Length=5+x=10cm

Perimeter=2(l+w)=2(5+10)=30cm

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Answer 2

Step-by-step explanation:

let width be x cm

given condition is x+5 cm

area= 50cm^2

area of a rectangle= length* width

50cm^2=(x+5)(x)

50=x^2+5x

x^2+5x-50=0

x^2+10x-5x-50=0

x(x+10)-5(x+10)=0

(x-5)(x+10)=0

x= 5 and x=-10

it cannot be negative

so

x= 5

width= 5 cm

length= x+5= 5+5=10cm

perimeter of the r rectangle = 2(l+w)

=2(10+5)

=2(15)

= 30cms