Question

The length of rectangle is 7 more than its width. if x is the width then what is the area of the rectangle

Answer 1

Width is x
Length is x+7
Area is Length × Width = (x+7) × x
= x² + 7x

Answer 2

Answer:

The required area of the rectangle is $x^{2} +7x$

Step-by-step explanation:

Concept:

The quantity of space occupied by a flat surface with a specific shape is referred to as the area. It is calculated as a "number of" square units (square centimeters, square inches, square feet, etc.) The number of unit squares that can fit inside a rectangle is called its area.

Area of a Rectangle = (Length × Breadth) square units

Given:

The length of the rectangle is $7$ more than the width.

The width is $x$

To find:

The objective is to find out the value of the area of the rectangle.

Solution:

We know, Area of rectangle= length × width

width$=x$

Length$=x+7$

The area of the rectangle:

$=(x+7)$ × $x$

$=x^{2} +7x$ square.units

Therefore, the area of the rectangle is $(x^{2} +7x)$ square units.

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