Question

The length of rectangle is 8m more than its breadth . If its area is 660m2 . find its perimeyer. answer me giving solution .
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Answer 1

Step-by-step explanation:

Given:-

The length of rectangle is 8m more than its breadth . Its area is 660m².

To find :-

Find its perimeter ?

Solution :-

Let the breadth of a rectangle be X m

Then, The length = breadth + 8 m

=> (X+8) m

Length of the rectangle = (X+8) m

We know that

Area of a rectangle = lb sq.units

Area of the given rectangle

=> (X+8)×X m²

=> (X²+8X ) m²

According to the given problem

Area of the given rectangle = 660 m²

=> X²+8X = 660

=> X²+8X-660 = 0

=> X²+30X-22X-660 = 0

=> X(X+30)-22(X+30) = 0

=> (X+30)(X-22) = 0

=> X+30 = 0 or X-22 = 0

=> X = -30 or X = 22

X can not be negative.

Therefore, X = 22 m

Breadth of the given rectangle = 22 m

Length of the given rectangle = 22+8 = 30 m

We know that

Perimeter of a rectangle = 2(l+b) units

Perimeter of the given rectangle

=> 2(30+22) m

=> 2(52) m

=> 104 m

Answer:-

Perimeter of the given rectangle is 104 m

Used formulae:-

→Area of a rectangle = lb sq.units

→Perimeter of a rectangle = 2(l+b) units

• l = length
• b = breadth

Answer 2

Let the breadth be x

According to Ques.

length = x+8

Area= 660m^2

We know,

Area= l*b

or, 660= (x+8*x)

or, 660= x^2+8x

or, 0= x^2 +8x-660

or, 0= x^2+(30-22)x -660

or, 0=x^2 +30x-22x-660

or, 0=x(x+30)-22(x+30)

or, 0=(x-22)(x+30)

Either, x-22=0 Or, x+30=0

x=22 x=-30

Now, putting value in above eq:n

x+8 = 22+8= 30

x= 22

We know,

Perimeter= 2(l+b)

= 2(30+22)

= 60+44

= 104

Therefore, perimeter of given rectangle is 104cm.