The length of rectangle is increased by 25% by what percent of the breadth to be decreased to maintain the same area
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The area of ractangle is l*b.
The length is increased by 50 % which means that the the length becomes 150% of original length {say 1.5 times the original length}.
The area should be l`*b`
Where l` is equal to 1.5 l
The two area should be equal then
l`*b`= l*b
1.5l* b`= l*b
b`= (l*b) /1.5l
= 2/3 b
Hence the width should be decreased to 2/3b.
The length is increased by 50 % which means that the the length becomes 150% of original length {say 1.5 times the original length}.
The area should be l`*b`
Where l` is equal to 1.5 l
The two area should be equal then
l`*b`= l*b
1.5l* b`= l*b
b`= (l*b) /1.5l
= 2/3 b
Hence the width should be decreased to 2/3b.
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