The length of rectangle is three times its breadth .if its perimeter is 64 cm, find the sides of rectangle
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Answered by
8
Answer:
ez pz
Step-by-step explanation:
given that
l=3b......... (1)
perimeter of a rectangle = 2(l+b)
64= 2(l+b)
64= 2(3b+b) - by (1)
64 = 6b+2b
64 = 8b
b = 8
in (1)
l=3(8)
l=24
Answered by
6
Hey friend, Here is your answer-
Let the breadth of the rectangle is x.
Then length is 3x
From the given condition,
Perimeter = 2 ( l + b )
64 = 2 (x + 3x)
64 = 2 × 4x
64 = 8x
x = 8
Therefore the length of rectangle is 24 cm and breadth is 8 cm.
The sides of rectangle are 24 cm , 8 cm , 24 cm and 8 cm.
Hope it will help you.
Please Please please make me brainliest
Let the breadth of the rectangle is x.
Then length is 3x
From the given condition,
Perimeter = 2 ( l + b )
64 = 2 (x + 3x)
64 = 2 × 4x
64 = 8x
x = 8
Therefore the length of rectangle is 24 cm and breadth is 8 cm.
The sides of rectangle are 24 cm , 8 cm , 24 cm and 8 cm.
Hope it will help you.
Please Please please make me brainliest
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