Question

the length of rectangle is twice the width. it's perimeter is 4 cm more than the length. find its area in cm2 ​

Answer 1

2223 cm

Step-by-step explanation:

Let x be the width of the rectangle, and since the length is 4 cm more than twice the width, this should be represented as 2x+4 .

To solve: P=2L+2W

2(2x+4)+2(x)=64

4x+8+2x=64

6x=64–8

6x=56

6x6=566

x=913 cm , - the width, and the length is 2223 cm

Answer 2

Answer:

Area = 2 $cm^{2}$

Step-by-step explanation:

Let the width of the rectangle be x

So, length= 2x, Perimeter= 2x+4

Now,

Perimeter Of Rectangle = 2(l+b)

2x+4= 2(2x+x)

2x+4= 4x+2x

4= 4x+2x-2x

4= 4x

4/4=x

1 cm=x

Width= x= 1 cm

Length= 2x= 2×1= 2 cm

Area Of Rectangle= L×B

                              = 2×1

                              = 2 $cm^{2}$

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