Question

the length of rectangle is two times it's widththe perimeter of the rectangle is 180cm find the dimensions of rectangle and also find its area
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Answer 1

Answer:

l=2b

P=2(I + b) = 2(2b+b)

P = 6b

6b = I80

b = 30 cm. Ans

I=2b=60cm. Ans

Area =1xb=6ox30=1800cm2. Ans

Answer 2

$\underbrace{ \boxed{ \tt \pink S \gray ol \blue ut \red io \purple n}}$

Let the width of the rectangle be x.

It is given that the length of the rectangle is twice its width, so the length is 2x.

Now,

We know that the perimeter of a rectangle is twice the sum of its length and width.

The perimeter is given as 180 cm.

So, Perimeter of rectangle = 2(L+B)

$\implies \red{ \tt 180cm = 2(2 x+ x)}$

$\implies \blue{ \tt 180cm = 4 x+ 2x}$

$\implies \purple{ \tt 180cm = 6x}$

$\implies \pink{ \tt \frac{ \cancel{180}}{ \cancel6} = x}$

$\implies \gray{ \tt x = 30cm}$

$\tt So, the \: width \: of \: rectangle \: is \\ \tt x = 30cm \: and \: the \: length \: of \: rectangle \\ \tt is \: 2x = 2 \times 30 = 60cm.$

$\huge \tt Hence, \: dimensions \\ \huge \tt of \: rectangle \: is \\ \huge \boxed{ \tt30 \times 60}$