the length of rectangle us greater than the breadth by 18cm if both length and breadth increased by 6 cm then area increased by 168 cm square find the length and the breadth of rectangle
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The length of a rectangle is greater than the breadth by 18 cm. If the length and breadth are increased by 6 cm, then the area by 168, what is the length and breadth?
Initially assume breadth =x,then length = (x+18)
Area of rectangle = length * breadth
Area = x(x+18)=x^2+18x
Area after increasing length and breadth by 6 cm was (x+6)*(x+24)
New area = x^2+30x+144 ,which is equal to previous area increased by 168
Therefore final equation was
x^2+18x+168= x^2+30x+144
Solving x=2cm ( ie.., breadth of rectangle)
And length = 2+18= 20 cm
Initially assume breadth =x,then length = (x+18)
Area of rectangle = length * breadth
Area = x(x+18)=x^2+18x
Area after increasing length and breadth by 6 cm was (x+6)*(x+24)
New area = x^2+30x+144 ,which is equal to previous area increased by 168
Therefore final equation was
x^2+18x+168= x^2+30x+144
Solving x=2cm ( ie.., breadth of rectangle)
And length = 2+18= 20 cm
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