the length of rectangular field is 2 metre more than its breadth if the perimeter is 32 M find the area
Answers
Answered by
14
perimeter=2(LB)
32. = 2 (B+2+B)
16=2+2B
16-2=2B
14=2B
B=7
area=7×9=63m2
32. = 2 (B+2+B)
16=2+2B
16-2=2B
14=2B
B=7
area=7×9=63m2
Answered by
16
let the breadth of the rectangle = x
length of the rectangle = x + 2 m
GIVEN :-
perimeter of rectangle = 32 m
To find :- Area of the rectangle
Let's come to answer :-
perimeter of rectangle = 2 ( l + b )
2 ( x + 2 + x ) = 32 m (given)
2 × ( 2x + 2 ) = 32 m
4x + 4 = 32 m
4x = 32 - 4 m
4x = 28 m
x = 28 m / 4 = 7m
so , breadth = 7m and ;
length = 7 + 2 m = 9 m
Now ;
Area of the rectangle = length × breadth
9m × 7m
63 m^2 answer
hope this helps you
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